Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8188435
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T02:54:44+00:00 2026-06-07T02:54:44+00:00

My table: id attribute 1 2 1 2 2 3 2 4 5 1

  • 0

My table:

id attribute
1  2
1  2
2  3
2  4
5  1
5  1
6  3
6  3
6  5

Now I want only to output those id with attribute, if the attribute is the same for each id.

In this sample table, the output would be

id attribute
1  2
5  1
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-07T02:54:45+00:00Added an answer on June 7, 2026 at 2:54 am

    You could use this approach:

    SELECT DISTINCT id, attribute 
    FROM test t1 
    WHERE (SELECT count(DISTINCT attribute) 
           FROM test t2 
           WHERE t2.id = t1.id) = 1
    

    A better approach could be:

    SELECT
       DISTINCT t1.id, t1.attribute
    FROM
       test t1,
       (
          SELECT
             id,
             count(DISTINCT attribute) COUNT
          FROM
             test
          GROUP BY
             id
          HAVING
             COUNT = 1
       ) t2
    WHERE
       t1.id = t2.id
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I imagine this pertains to Hibernate only (I'm just now beginning to use these
One attribute in a table became corrupted after a certain point in a table
in a Table there is a single attribute(column).it contains numbers.Some are repeated(2 or 3
Is declaring an attribute of a table as UNIQUE equivalent to declaring it as
I defined an attribute in my table of type serial4 , so when I
How can one update an attribute value in DynamoDB table to ? one option
I would like to add custom attributes to a MySQL table which I can
This question comes very closely to what I'm after: Replace an Attribute in the
Let's say that I want to build 2 different sets of tablet-only layouts. One
Basically, I have a table with multiple editors like this: <table> <tr> <td>@Html.EditorFor(x =>

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.