Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4575486
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T20:04:15+00:00 2026-05-21T20:04:15+00:00

Normal list comprehensions occur this way: new_list = [f(x) for x in l] What

  • 0

Normal list comprehensions occur this way:

new_list = [f(x) for x in l]

What is the most succinct and readable way to create new list in Python similar to this:

new_list = [f(x) while condition is True]
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-21T20:04:15+00:00Added an answer on May 21, 2026 at 8:04 pm

    Keep it simple:

    new_list = []
    while condition:
        new_list.append(f(x))
    

    There is no benefit to forcing something into a single expression when it is more clearly written as separate statements.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

What is the most concise way of converting a java.util.List into a normal JavaFX
The normal JSON approach looks something like this: { list: [ { header1: some
I have loaded data to normal list view from JSON array like this JSONArray
Normal way: class A: def __init__(self): self.a.b.c = 10 def another_method(self): self.a.b.c = self.a.b.c
A normal UserControl looks like this in XAML: <UserControl x:Class=mynamespace.foo ...namespaces...> <!-- content -->
I currently have a normal SharePoint list with about 15 columns or so. I
I have a normal method public List<string> FindNearByCity(string targetCity) { // ... some implementation
Assuming this list nestedList = [a, b, [1, 2, 3], c,[4, 5, 6, [100,
In normal array list initialization, We used to define generic type as follows, List<String>
I have a normal unordered list <ul> <li>Item 1</li> <li>Item 2</li> <li>Item 3</li> <li>Item

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.