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Home/ Questions/Q 445369
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T21:21:49+00:00 2026-05-12T21:21:49+00:00

Okay, I know this is a common enough question, but all the solutions I’ve

  • 0

Okay, I know this is a common enough question, but all the solutions I’ve found thus far have involved a missing semi-colon or curly brace, both of which I know is not the case for me.

I have a class that works FINE with this variable assignment:

session.php:

<?php

   class session {
     ... 
     var $host = 'localhost';
     ...
   }

?>

Great. But I want to have my database details in another file, so I did this:

db_creds.php:

<?php

   var $db_creds = array(
      'host' => 'localhost',
      ...
   );

?>

session.php

<?php

   include('db_creds.php');

   class session {
     ... 
     var $host = $db_creds['host'];
     ...
   }

?>

Which then gave me this error: Parse error: syntax error, unexpected T_VARIABLE in ../session.php on line 74, where line 74 is my var $host assignment.

I even tried doing this in session.php, just to be sure the problem wasn’t in the include:

session.php

<?php

   # include('db_creds.php');

   class session {
     ...
     var $db_host = 'localhost';
     var $host = $db_host;
     ...
   }

?>

… but that just throws the same error as above.

Can anyone tell me what’s happening here? I’m at my wits end!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T21:21:49+00:00Added an answer on May 12, 2026 at 9:21 pm

    Variables are not allowed here, properties must be initialized by constants in PHP:

    […] this initialization must be a constant value

    [Source: php.net manual]

    Use the constructor to intialize the value properly:

    class session {
        var $host;
    
        function __construct() {
            $this->host = $db_creds['host'];
        }
    }
    
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