Question

Original Form

  <?php
echo '<td><form action="episodesdelete.php" method="POST">';
echo '<input type="hidden" name="epid" value="'.$row['epid'].'">';  
?>

episodesdelete.php

<?php
$connection = mysql_connect("localhost","root","")
or die ("Couldn't Connect To Server");
$db = mysql_select_db("shows", $connection)
or die ("Couldn't Select Database");
$query = "DELETE FROM shows WHERE epid= "'.$_POST['epid']'";
$result = mysql_query($query)
or die ("Query Failed: " . mysql_error());

?>

Answer 1

First of all, you have in-correct usage of double quotes:

$query = 'DELETE FROM shows WHERE epid= ".$row['epid']"';

Should be:

$query = "DELETE FROM shows WHERE epid= ".$row['epid']";

---

You have one more problem:

You also need to use $_POST array with correct field name like:

$query = "DELETE FROM shows WHERE epid= " . $_POST['id'];

Because you are using POST as method of the form:

<form action="episodesdelete.php" method="POST">

You need to use $_POST

And because your hidden field is named id:

echo '<input type="hidden" name="id" value="'.$row['epid'].'">';

You need to specify that in your query:

$_POST['id']

So here is how your query should be:

$query = "DELETE FROM shows WHERE epid= " . $_POST['id'];