Question

page1.php

  echo '<form action="page2.php" name="myform"><table>
        <tr><td>name:<input type="text" name="n"></td></tr>
        <tr><td>Choose Desc<select name="desc" value="0">
                  $descriptions = mysql_query('SELECT desc FROM desc_table');
                  while($row=mysql_fetch_array($descriptions))
                  {
                     $des = $row['desc'];
                     echo '<option>'.$des.'</option>';
                  }
                  </select>
       </td></tr>';
          <tr><td>Description:<textarea rows="10" cols="10" name="desc" value="1"></textarea></td>  </tr>     
 <tr><td><input type="submit" value="submit"></td></tr>
 </table>
  </form>';

Page2.php

 $n = $_POST['n'];
 $desc = $_POST['desc'];
 $sql = "INSERT INTO new (name,desc)
                VALUES ($n,$desc)";
 mysql_query($sql);

I need to store either one description either by selecting the description or typing the description in the textarea, but only one description should get stored to database.

Answer 1

Change into this:

$n = $_REQUEST['n'];
$desc = $_REQUEST['desc'];
$sql = "INSERT INTO new (name,desc)
            VALUES ("$n","$desc")";
mysql_query($sql);

And add a method to your tag

<FORM action="resultscript.php" method="POST"></FORM>

And try again 😉

BTW: If the variables you are putting in your SQL might contain strings, you need to put them in double quotes (“)