Question

<?php
    mysql_connect("localhost","root","");
    mysql_select_db('db2012');
    $uid = 8;
    $mid = 10;

    $q = mysql_query("select friend from users_friends where user = $uid") or die(mysql_error());
    if(mysql_num_rows($q) > 0)
    {

        while($r=mysql_fetch_array($q))
        {
            $qq = mysql_query("select friend from users_friends where user = $mid") or die(mysql_error());
            while($rr = mysql_fetch_array($qq))
            {
                if($r[friend]==$rr[friend])
                {
                    $friend_name_query = mysql_query("select name from users where uid = '$rr[friend]'") or die();
                    $friend_name = mysql_fetch_array($friend_name_query);
                    echo $friend_name[name];
                }
            }
        }   
    }


?>

This query is working but any other way out to use less queries ? i m a beginner programmer please let me know if there is n e thng …

Answer 1

You should use just one query:

$query = 'SELECT u.name
    FROM users_friends f1 
      INNER JOIN users_friends f2 ON (f2.friend = f1.friend)
      INNER JOIN user u ON (u.uid = f2.friend)
    WHERE f1.user = "'. $uid. '"
      AND f2.user = "'. $mid .'"';

run the query

$q = mysql_query($query) or die(mysql_error());

and do the while loop

while($r=mysql_fetch_array($q)){
  echo $r['name'];
}

You only need the if(mysql_num_rows($q) > 0) statement if you do an else, otherwise you can just use the while