Question

Possible Duplicate:
char [length] initialization and dealing with it

I have:

char d[7];

What is wrong regarding following:

At this moment no memory allocated for variable d. Now I’m going to initialize it:

d="bbbbbb";

After this type initialization, there would be no need to free memory; it will be done automatically.

How to know was char[] initialized? I need a pattern like

if (filled(d)){..}

How to fill char[] with one kind of characters?

Answer 1

OK if you want to fill your char with ‘b’ character you CAN do it this way

  char d[7];
  int i;
  for (i = 0; i < 7; i++) {
      d[i] = 'b';
  }