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Finding local IP addresses using Python's stdlib

To get my localhost IP address I do socket.gethostbyname(socket.gethostname()). But it gives me the answer 127.0.0.1.
If I do an_existing_socket.getsockname()[0] I get the answer 0.0.0.0.

I need my ‘real’ ip address (for instance 192.168.x.x) to modify a configuration file. How could I get it?

Answer 1

I generally use this code:

import os
import socket

if os.name != "nt":
    import fcntl
    import struct

    def get_interface_ip(ifname):
        s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
        return socket.inet_ntoa(fcntl.ioctl(s.fileno(), 0x8915, struct.pack('256s',
                                ifname[:15]))[20:24])

def get_lan_ip():
    ip = socket.gethostbyname(socket.gethostname())
    if ip.startswith("127.") and os.name != "nt":
        interfaces = [
            "eth0",
            "eth1",
            "eth2",
            "wlan0",
            "wlan1",
            "wifi0",
            "ath0",
            "ath1",
            "ppp0",
            ]
        for ifname in interfaces:
            try:
                ip = get_interface_ip(ifname)
                break
            except IOError:
                pass
    return ip

I don’t know it’s origin, but it works on Linux/Windows.

Edit:

This code is used by smerlin in this stackoverflow question.