Question

Possible Duplicate:
In PHP, after assigning a file pointer resource to a variable with fopen(), how can I get the file name from the variable?

Example:

$this->resource = fopen('c:\wamp\www\some_file.txt', 'a');

Now if I try to access $this->resource later, in a different method I get:

Resource id #51: stream

Can I get the actual file path too?

Answer 1

in addtitional aswer with voodoo417, you can get info about the file like this

$infos = pathinfo('/www/htdocs/inc/lib.inc.php');

echo $infos ['dirname'], "\n";
echo $infos ['basename'], "\n";
echo $infos ['extension'], "\n";
echo $infos ['filename'], "\n";

———————- OUTPUT ————————-

/www/htdocs/inc
lib.inc.php
php
lib.inc

//from php.net

also see fileinfo extention.