Question

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PHP: “Notice: Undefined variable” and “Notice: Undefined index”

i am getting “ranksection” array at run time and after implementing ksort on “ranksection” i wanna move its data upward on null index as i am printing ranksection before moving its data upward if there were any free array i am successfully getting what i want but it also giving error “Undefined Index” i dont know why my code is,

$sortvar = count($ranksection);
$seqnum = 0;

for ($var = 0; $var <= $sortvar; $var++) {
  if ($ranksection[$var] !=  null) {
    $sequence[$seqnum] = $ranksection[$var];
    $seqnum++;
  }
}

print_r($sortvar);
print_r($ranksection);
print_r($sequence);

the result is,

3

Array ( [1] => Self Introduction [2] => Experience in Econometrics and multivariate S [3] => Experience ) 

Array ( [0] => Self Introduction [1] => Experience in Econometrics and multivariate S [2] => Experience )

Hopes for your suggestions

Answer 1

See your print_r section of second array it starts with index 1 and your $var assigned to 0.
Now here you are trying to access the 0th index. that is why you’re getting this error.

Try to use foreach

foreach($ranksection as $key => $value ) {
  if ($ranksection[$key] !=  null) {
    $sequence[$seqnum] = $ranksection[$key];
    $seqnum++;
  }
}