Question

Possible Duplicate:
PHP Pass by reference in foreach

Why does the value change for both items in array? I’m just trying to change the value of the key that is equal to $testitem.

Desired result of following code:
item:5 Quantity:12
item:6 Quantity:2

The current result of the following code is:
item:5 Quantity:12
item:6 Quantity:12

<?php
            $items = array(
                '5' => '4',
                '6' => '2',
            );

            $testitem = '5';
            $testvalue = '8';

            foreach($items as $key => &$value)
            {   
                if ($key == $testitem)
                {
                    $value = $value + $testvalue;   
                }
            }

            foreach($items as $key => $value)
            {                       
                print 'item:'.$key.' Quantity:'.$value.'<br/>';
            }
?>

Answer 1

The problem comes when you attempted to pass the $value variable as a reference. You will be able to achieve your desired result by modifying your foreach loop to look like this –

foreach($items as $key => $value){   
  if ($key == $testitem){
    $items[$key] = $value + $testvalue;   
  }
}

Simply use the current $key or the value of $testitem for that matter, as a reference to your $items array – and modify the contents like that.