Question

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Python regular expressions – how to capture multiple groups from a wildcard expression?

I cannot access the group for 3rd or 5th element in the following regex:

>>> x = 'f 167 2958 335 3103 0'
>>> re.search('.(\s\d+){5}', x).group()
'f 167 2958 335 3103 0'
>>> re.search('.(\s\d+){5}', x).group(1)
' 0'
>>> # how do i access no 2958 and 3103

I know I can achieve the above with pattern = ‘.\s\d+\s(\d+)\s\d+\s(\d+)\s\d+’, but thats lame.

Thanks,
Amit

Answer 1

You can use re.findall for this.

result = re.findall('\s\d+', x)

print result[1]  # 2958
print result[3]  # 3103