Question

Possible Duplicate:
Retain precision with Doubles in java

import static java.lang.System.out;
public class q2{  
    public static void main(String args[]){  
        double x=4.02, y=0.05;  
        out.println(x+y);  
    }  
}

Output:

4.069999999999999

Why is it outputting the that. I thought it would be 4.07. Please explain why this happens in java ?

Sorry for the inaccurate Question title. I can’t have a better title than this

Answer 1

That is because some numbers — such as 0.1 — cannot be represented exactly in binary floating-point.

Consider reading the following article:

• What Every Computer Scientist Should Know About Floating-Point
  Arithmetic