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Home/ Questions/Q 4043938
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T13:11:26+00:00 2026-05-20T13:11:26+00:00

PROBLEM: I have two tables, animal table and placeholder table. I want to do

  • 0

PROBLEM:

I have two tables, animal table and placeholder table. I want to do an UPDATE
on the animal table so that the appropriate blanks get filled in. The animal
table is not properly normalized.

Is it possible to do this with pure MySQL SQL statements and not resorting to
looping inside a program or script?

EXAMPLE:

== Here is the “before” ==

animal            placeholder
1 | dog           1 | dog   | log 
1 | snog          2 | cat   | mat
1 | _blank_       3 | bird  | word
2 | cat
2 | sat
2 | _blank_
3 | bird
3 | heard
3 | _blank_

== Here is the “after” ==

animal            placeholder
1 | dog           1 | dog   | log 
1 | snog          2 | cat   | mat
1 | log           3 | bird  | word
2 | cat
2 | sat
2 | mat
3 | bird
3 | heard
3 | word

QUESTION:

Can you construct a MySQL SQL statement that will use UPDATE to transform
“before” into “after”??

I am assuming it will be necessary to use JOIN since the query needs to know the correct place to put the placeholders.

== Solution ==

UPDATE animal a
SET name = (
SELECT noun
FROM placeholder
WHERE (
a.id = id
)
) WHERE a.name is null;

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T13:11:27+00:00Added an answer on May 20, 2026 at 1:11 pm

    maybe something similar to this :

    update animal a
    set name = ( select col2 from placeholder where a.name is null and a.id = id )
    
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