public class Common {
public synchronized void synchronizedMethod1() {
System.out.println("synchronizedMethod1 called");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("synchronizedMethod1 done");
}
public void method1() {
System.out.println("Method 1 called");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Method 1 done");
}
}
public class MyThread extends Thread {
private int id = 0;
private Common common;
public MyThread(String name, int no, Common object) {
super(name);
common = object;
id = no;
}
public void run() {
System.out.println("Running Thread" + this.getName());
try {
if (id == 0) {
common.synchronizedMethod1();
} else {
common.method1();
}
} catch (Exception e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
Common c = new Common();
MyThread t1 = new MyThread("MyThread-1", 0, c);
MyThread t2 = new MyThread("MyThread-2", 1, c);
t1.start();
t2.start();
}
}
Output:
Running ThreadMyThread-1
synchronizedMethod1 called
Running ThreadMyThread-2
Method 1 called
synchronizedMethod1 done
Method 1 done
I would like to find a way to prevent method1() from running when i called synchronizedMethod1. Unless I’m mistaken all methods are called and Java compiles them during and before runtime regardless if it’s synchronized or not.
Should i have used a Lock object instead and/or not also make method1() a synchronized method?
If you want
method1andsynchronizedMethod1to be mutually exclusive then you need to guard them with the same lock. Whether this is using aLockor simply callingsynchronizeon the same Object instance, the outcome is roughly the same.On the off chance you want multiple threads to be allowed to execute
method1but not whensynchronizedMethod1is being invoked, you need aReadWriteLockto accomplish that.