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Home/ Questions/Q 6003325
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:06:19+00:00 2026-05-23T01:06:19+00:00

public DateTime EnterDeparture() { Console.WriteLine(Enter Year:); return new DateTime().AddYears(int.Parse(Console.ReadLine())); } // This will return

  • 0
       public DateTime EnterDeparture()
        {
            Console.WriteLine("Enter Year:");
            return new DateTime().AddYears(int.Parse(Console.ReadLine()));
        }
    // This will return new DateTime(Without assigned Year)  Cause DateTime is value type.
           public DateTime EnterDeparture()
                {
                    DateTime EnterDeparture = new DateTime();
                    Console.WriteLine("Enter Year:");
                    EnterDeparture.AddYears(int.Parse(Console.ReadLine()));
                    return EnterDeparture;
                }

How to work with several fields in DateTime ? (Year,Days for example) Default constructors aren’t suitable.

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:06:20+00:00Added an answer on May 23, 2026 at 1:06 am

    The DateTime.AddXXX methods return new DateTime instances, the existing struct does not change. Since each method returns a new instance, you can chain the method calls together. At the very least, you want to capture each return value into a variable. For example:

    DateTime myDate = DateTime.Today;
    DateTime tomorrowAtNoon = myDate.AddDays(1).AddHours(12);
    

    You could have also written it like

    DateTime tomorrow = myDate.AddDays(1);
    DateTime tomorrowAtNoon = tomorrow.AddHours(12);
    

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