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Home/ Questions/Q 579371
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:21:36+00:00 2026-05-13T14:21:36+00:00

public static String[] removeString (String[] original) { String[] newString; List<String> list = new ArrayList<String>(Arrays.asList(original));

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public static String[] removeString (String[] original) { 
  String[] newString; 
  List<String> list = new ArrayList<String>(Arrays.asList(original)); 

  list.remove(0); 
  newString = list.toArray(original); 
  return newString; 
}

I’m trying to use the above code to remove the first string from an array of strings; however, it seems that although I do succeed in removing the first string from the array, I also made the last string in the array null. How can I make the array itself shorter?

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:21:36+00:00Added an answer on May 13, 2026 at 2:21 pm

    Change your last-but-one line to:

    NewString = list.toArray(new String[list.size()]);
    

    The toArray(..) method takes as an argument a list which it tries to fill with the list data. You are passing a list of length 3, so the last element stays empty. With my suggestion you create a new array with the new size of the list.

    As a sidenote: I’d advice that you revisit your naming conventions. According to the recommended naming conventions your method and variable names should start with a lower-case letter

    Update: but you’d better use Arrays.copyOfRange(..) as suggested by others.

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