Question

Python 2.5 won’t let me use this syntax:

try:
    code_that_raises_exception()
except Exception as e:
    print e
    raise

So how should I print information about an exception?

Thanks

EDIT: I’m writing a plugin for a program that includes kind of a pseudo python interpreter. It prints print statements but doesn’t show exceptions at all.

Answer 1

the ‘as’ keyword is a python 3 (introduced in 2.6) addition, you need to use a comma:

try:
    code_that_raises_exception()
except Exception, e:
    print e
    raise