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Home/ Questions/Q 8335499
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:41:43+00:00 2026-06-09T03:41:43+00:00

Python beginner running 2.7 I want to have a list which is constantly summed

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Python beginner running 2.7

I want to have a list which is constantly summed as new values are added to it. However, I keep getting Attribute Error: ‘int’ object has no ‘append’ function. I understand the basic problem – you can’t append to an integer – but would like to find a workaround. Do any of you have a solution?

Simplified version of my code, and then a possible solution I’d like to avoid.

my_list = sum([])

def myfunction (i):
    return i 

thing = myfunction (1)
my_list.append(thing)

thing2 = myfunction (2)
my_list.append(thing2)

def function_2 (a,b):
    #function which uses my_list

I suppose I could do the following solution, but I would like to avoid it (interferes with existing code).

my_list = []
summed_my_list = sum (mylist)

def myfunction (i):
    return i 

thing = myfunction (1)
my_list.append(thing)

thing2 = myfunction (2)
my_list.append(thing2)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:41:44+00:00Added an answer on June 9, 2026 at 3:41 am

    If you don’t need the list the question is trivial, because you simply need

    total += value 
    

    at each step.

    Class derived from list

    If you do need both the list and the sum (which autoupdates) you could create a class derived from list such as – which should auto sum when you append to it.

    class mylist(list):
        tot = 0
        def append(self, value):
            super(mylist, self).append(value)
            self.tot += value
    

    Example usage

    #!/usr/bin/python
    
    class mylist(list):
      tot = 0
      def append(self, value):
        super(mylist, self).append(value)
        self.tot += value
    
    
    a = mylist()
    a.append(1)
    a.append(20)
    print a.tot
    print a
    

    output:

    21
    [1,20]
    
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