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Home/ Questions/Q 8073929
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T14:29:40+00:00 2026-06-05T14:29:40+00:00

Quick one, I have a table, with the following structure id lid taken 1

  • 0

Quick one,

I have a table, with the following structure

id  lid  taken
1   1    0
1   1    0
1   1    1
1   1    1
1   2    1

Pretty simply so far right?

I need to query the taken/available from the lid of 1, which should return

taken  available
2      2

I know I can simply do two counts and join them, but is there a more proficient way of doing this rather than two separate queries?

I was looking at the following type of format, but I can not for the life of me get it executed in SQL…

SELECT
   COUNT(case taken=1) AS taken, 
   COUNT(case taken=0) AS available FROM table
WHERE 
   lid=1

Thank you SO much.

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  1. Editorial Team
    Editorial Team
    2026-06-05T14:29:41+00:00Added an answer on June 5, 2026 at 2:29 pm

    Your query is correct just needs juggling a bit:

    SELECT
       SUM(case taken WHEN 1 THEN 1 ELSE 0 END) AS taken, 
       SUM(case taken WHEN 1 THEN 0 ELSE 1 END) AS available FROM table
    WHERE 
       lid=1
    

    Alternatively you could do:

    SELECT
       SUM(taken) AS taken, 
       COUNT(id) - SUM(taken) AS available 
    FROM table
    WHERE 
       lid=1
    
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