Question

Say I have

Bin = <<"10=123">>

This function

binary:split(Bin, <<"10=">>),

splits it into

[<<"10=">>, <<"123">>]

Instead I need it to match the last 3 numbers.
Even if its 345 or 777.
The one for sure thing is that it will always be 3 numbers.

So it would instead match the entire pattern

Im not too good with binaries but I believe I am looking for something like

 binary:split(Bin, <<01,"10=", 3/binary>>),

Answer 1

I’m not 100% sure what you mean but if you only want to match the <<“123″>> part then you could simply do:

1> <<"10=", Rest/binary>> = <<"10=123">>.
<<"10=123">>
2> Rest.
<<"123">>

If you don’t want to match at all on the <<“10=”>> part just replace it above with “_:3/binary”.

If this is what you want then your original way would have worked just as good:

1> Bin = <<"10=123">>.
<<"10=123">>
2> [_,Rest] = binary:split(Bin, <<"10=">>).
[<<>>,<<"123">>]
3> Rest.
<<"123">>