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Home/ Questions/Q 8373003
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Editorial Team
  • 0
Editorial Team
Asked: June 9, 20262026-06-09T14:34:20+00:00 2026-06-09T14:34:20+00:00

Scenario: trait A { function calc($v) { return $v+1; } } class MyClass {

  • 0

Scenario:

trait A {
    function calc($v) {
        return $v+1;
    }
}

class MyClass {
    use A;

    function calc($v) {
        $v++;
        return A::calc($v);
    }
}

print (new MyClass())->calc(2); // should print 4

This code doesn’t work, and I cannot find a way to call a trait function like it was inherited. I tried calling self::calc($v), static::calc($v), parent::calc($v), A::calc($v) and the following:

trait A {
    function calc($v) {
        return $v+1;
    }
}

class MyClass {
    use A {
        calc as traitcalc;
    }

    function calc($v) {
        $v++;
        return traitcalc($v);
    }
}

Nothing works.

Is there a way to make it work or must I override completely the trait function which is much more complex than this 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T14:34:21+00:00Added an answer on June 9, 2026 at 2:34 pm

    Your last one was almost there:

    trait A {
        function calc($v) {
            return $v+1;
        }
    }
    
    class MyClass {
        use A {
            calc as protected traitcalc;
        }
    
        function calc($v) {
            $v++;
            return $this->traitcalc($v);
        }
    }
    

    The trait is not a class. You can’t access its members directly. It’s basically just automated copy and paste…

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