Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8366789
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 9, 20262026-06-09T13:00:03+00:00 2026-06-09T13:00:03+00:00

<script> $(function() { $( #sortable ).sortable(); $( #sortable ).disableSelection(); }); </script> <div class=demo> <ul

  • 0
<script>
    $(function() {
        $( "#sortable" ).sortable();
        $( "#sortable" ).disableSelection();
    });
    </script>


<div class="demo">

<ul id="sortable">
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 1</li>
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 2</li>
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 3</li>
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 4</li>
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 5</li>
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 6</li>
    <li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 7</li>
</ul>

</div><!-- End demo -->

I want to make the list sortable after appending to it another item by ajax , how I could do that ?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-09T13:00:05+00:00Added an answer on June 9, 2026 at 1:00 pm

    After appending new list items within in ajax success: function() {...} you can try:

    $( "#sortable" ).sortable('destroy').sortable().disableSelection();
    

    For example:

    $.ajax({
      url: '',
      type: '',
      success: function() {
        // all codes to append new list items
        // then add following line
    
        $( "#sortable" ).sortable('destroy').sortable().disableSelection();
    
        // do something else if need
      }
    });
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

<script type=text/javascript> $(#gallery).dragsort({ dragSelector: div, dragEnd: saveOrder, placeHolderTemplate: <li class='placeHolder'><div></div></li> }); function saveOrder() {
An absolutely common sortable case: <script> $(function() { $(#sortable).sortable(); }); </script> <ul id=sortable> <li>Item
I have the following code: <script> $(function() { $( #sortable ).sortable(); $( #sortable ).disableSelection();
This has me stumped. The follow code returns ,,,,,,: <script type=text/javascript> $(function() { $('#listB').sortable({
The JS script: function ShowUploadingAnimation() { $('#info_msg').html(<div style=\padding-top: 15px; height: 50px;\ align=\center\><img id=\uploading-img\ /></div>);
My html is: <div id=sortable> <div class=node></div> <div class=node></div> <div class=node></div> <div class=node></div> </div>
I have this jquery code: <script> $(function() { $( #sortable ).sortable({ stop: function(event, ui)
In this standard example http://jqueryui.com/demos/sortable/#connect-lists-through-tabs <script> $(function() { $( #sortable1, #sortable2 ).sortable().disableSelection(); var $tabs
I have created 20 radio button dynamically <script> $(function() { $( #sortable1, #sortable2 ).sortable({
<script type=text/javascript> $(function() { $( #sortable ).sortable({ update: function(event, ui) { var Order =

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.