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Home/ Questions/Q 8284307
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T11:03:28+00:00 2026-06-08T11:03:28+00:00

See the code below: #include <vector> #include <iostream> int main(int argc, char *argv[]) {

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See the code below:

#include <vector>
#include <iostream>
int main(int argc, char *argv[]) {
  std::vector<double> obj(10,0);
  std::cout << &obj << std::endl;
  std::cout << &obj[0] << std::endl;
}

I want to know the difference between these two addresses & thanks!
As I know, for a array like a[5], &a <=> &a[0] <=> a.

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  1. Editorial Team
    Editorial Team
    2026-06-08T11:03:30+00:00Added an answer on June 8, 2026 at 11:03 am

    &obj is the address of the vector itself, while the &obj[0] is the address of the data inside the vector.
    Arrays are nothing but data stored in them, so adress of array is effectively the same as adress of the data in it, while vector allocates its internal data on heap.

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