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Home/ Questions/Q 8178337
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:44:19+00:00 2026-06-06T23:44:19+00:00

Simple question. I have an array of 21 elements, and show every three of

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Simple question. I have an array of 21 elements, and show every three of them inside a <div> block. The code is something like this:

<?php
$faces= array(
  1 => 'happy',
  2 => 'sad',
  (sic)
  21 => 'angry'
);

$i = 1;
foreach ($faces as $face) {
  echo $face;
  $i++;
}

?>

The problem lies when this array doesn’t have 21 elements, sometimes it gets 24, an other times 17. How I wrap every three of them, and wrap alone the rest? I came up with using switch and case, but that works only when there are 21 elements only. I think I could count them beforehand and put a closing in the last one (even if it is a group of one element).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:44:21+00:00Added an answer on June 6, 2026 at 11:44 pm

    You already have most of it here. All you’re missing is something to test if you’re ready to wrap. So before you increment $i, try:

    $i = 1;
    
    foreach ($faces as $face)
    {
        echo $face;
    
        if ($i % 3 == 0)
        {
            echo "<br />"; // or some other wrapping thing
        }
        $i++;
    }
    

    This will ensure you’re wrapping every 3 faces, leaving any remainder in the final unit.

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