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Home/ Questions/Q 976165
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:42:14+00:00 2026-05-16T03:42:14+00:00

Simple question, simple code. This works: $x = &$_SESSION[‘foo’]; This does not: $x =

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Simple question, simple code. This works:

$x = &$_SESSION['foo'];

This does not:

$x = (isset($_SESSION['foo']))?&$_SESSION['foo']:false;

It throws PHP Parse error: syntax error, unexpected '&'. Is it just not possible to pass by reference while using the conditional operator, and why not? Also happens if there’s a space between the ? and &.

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:42:14+00:00Added an answer on May 16, 2026 at 3:42 am

    Simple answer: no. You’ll have to take the long way around with if/else. It would also be rare and possibly confusing to have a reference one time, and a value the next. I would find this more intuitive, but then again I don’t know your code of course:

    if(!isset($_SESSION['foo'])) $_SESSION['foo'] = false;
    $x = &$_SESSION['foo'];
    

    As to why: no idea, probably it has to with at which point the parser considers something to be an copy of value or creation of a reference, which in this way cannot be determined at the point of parsing.

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