Question

So, I already have the code to get all the words with digits in them out of the text, now all I need to do is to have the text all in one line.

with open("lolpa.txt") as f:
    for word in f.readline().split():
        digits = [c for c in word if c.isdigit()]
        if not digits:
            print(word)

The split makes the words all be in a different column.
If I take out the .split(), it types in the words without the digits, literally just takes the digits out of the words, and makes every letter to be in a different column.

EDIT: Yes, print(word,end=" ") works, thanks. But I also want the script to now read only one line. It can’t read anything that is on line 2 or 3 etc.

The second problem is that the script reads only the FIRST line. So if the input in the first line would be

i li4ke l0ke like p0tatoes potatoes
300 bla-bla-bla 00bla-bla-0211

the output would be

i like potatoes

Answer 1

In Python v 3.x you’d use

print(word, end='')

to avoid the newline.

in Python v 2.x

print word,

you’d use the comma at the end of the items you are printing. Note that unlike in v3 you’d get a single blank space between consecutive prints

Note that print(word), won’t prevent a newline in v 3.x.

—

Update based on edit in original post re code problem:

With input:

i li4ke l0ke like p0tatoes potatoes
300 bla-bla-bla 00bla-bla-0211

this code:

def hasDigit(w):
   for c in w:
      if c.isdigit():
         return True
   return False

with open("data.txt") as f:
    for line in f:
        digits = [w for w in line.split() if not hasDigit(w)]
        if digits:
            print ' '.join(digits)
#   break  # uncomment the "break" if you ONLY want to process the first line 

will yield all the “words” that do not contain digits:

i like potatoes
bla-bla-bla    <-- this line won't show if the "break" is uncommented above

Note:

The post was a bit unclear if you wanted to process only the first line of the file, or if the problem was that your script only processed the first line. This solution can work either way depending on whether the break statement is commented out or not.