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Home/ Questions/Q 8335781
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:46:33+00:00 2026-06-09T03:46:33+00:00

So I have something like this: <?php foreach($post_array as $post): ?> <div class=postBodyWrapper> <div

  • 0

So I have something like this:

<?php foreach($post_array as $post): ?>
    <div class="postBodyWrapper">
        <div class="vid-link">
            <script type="text/javascript">
                $(function() {
                    $(".vidthumb").append("<img class='thumb' src='<?php echo $post->vid_link; ?>'/>");
                });
            </script>
            <div class="vidthumb"></div>
        </div>
    </div>
<?php endforeach; ?>

Let’s say I have five posts in the $post_array. Then the <div class="vidthumb"></div> of each post will contain all five images (that are generated from the JavaScript code), instead of only the one that is supposed to. How can I fix it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:46:35+00:00Added an answer on June 9, 2026 at 3:46 am

    Try:

    <?php $i = 0; foreach($post_array as $post): ?>
    <div class="postBodyWrapper">
        <div class="vid-link">
            <script type="text/javascript">
                $(function() {
                        $("#vidthumb_<?php echo $i ?>").append("<img class='thumb' src='<?php echo $post->vid_link; ?>'/>");
                });
            </script>                           
            <div id="vidthumb_<?php echo $i++ ?>"></div>
        </div>
    </div>
    <?php endforeach; ?>
    

    By giving each vidthumb div you want the thumb to appear in a unique ID, you can now target the specific div’s instead of the first match.

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