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Editorial Team
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Asked: 2026-06-08T14:23:41+00:00

So I have the submit button that looks like this: <a href=# id=submitbutton onClick=document.getElementById(‘UploaderSWF’).submit();>

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So I have the submit button that looks like this:

<a href="#" id="submitbutton" 
onClick="document.getElementById('UploaderSWF').submit();">
<img src="../images/user/create-product.png" border="0" /></a>

When I double click it double submits obviously, and the problem is that
I’m saving the information in the database so I’ll have dublicate information there,
and I dont want that. This uploader uses flash and javscript and here is a little piece
of code that is relevant to the submit thing (if it helps)

$.fn.agileUploaderSubmit = function() {
    if($.browser.msie && $.browser.version == '6.0') {
        window.document.agileUploaderSWF.submit();
    } else {
        document.getElementById('agileUploaderSWF').submit();
        return false;
    }
}

Thank you guys.
I appreciate your help. This is really something I was unable to do myself
because I have such a little experience with js and I dont really know how
to do stuff.
THANKS.

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1 Answer

  1. Editorial Team

    Try this snipped:

    $('#your_submit_id').click(function(){
    $(this).attr('disabled');
});

    edit 1

    Oh, in your case it is a link and no submit button …

    var submitted = false;

$.fn.agileUploaderSubmit = function() {
    if ( false == submitted )
    {
        submitted = true;

        if($.browser.msie && $.browser.version == '6.0') {
            window.document.agileUploaderSWF.submit();
        } else {
            document.getElementById('agileUploaderSWF').submit();
        }
    }

    return false;
}

    edit 2

    To simplify this, try this:

    <!doctype html>

<html dir="ltr" lang="en">

<head>

<meta charset="utf-8" />

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

<script type="text/javascript">
<!--//--><![CDATA[//><!--
    $(document).ready(function()
    {
        $('#yourSubmitId').click(function()
        {
            $(this).attr('disabled',true);

            /* your submit stuff here */

            return false;
        });
    });
//--><!]]>
</script>

</head>
<body>

<form id="yourFormId" name="yourFormId" method="post" action="#">
    <input type="image" id="yourSubmitId" name="yourSubmitId" src="yourImage.png" alt="Submit" />
</form>​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​

</body>
</html>

    Use form elements, like <input type="image" />, to submit a form not a normal link.

    This works fine!

    Take a look at jQuery.post() to submit your form.

    Good luck.

    edit 3

    This works well for me too:

    <!doctype html>

<html dir="ltr" lang="en">

<head>

<meta charset="utf-8" />

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

<script type="text/javascript">
<!--//--><![CDATA[//><!--
    $(document).ready(function()
    {
        var agileUploaderSWFsubmitted = false;

        $('#submitbutton').click(function()
        {
            if ( false == agileUploaderSWFsubmitted )
            {
                agileUploaderSWFsubmitted = true;

                //console.log( 'click event triggered' );

                if ( $.browser.msie && $.browser.version == '6.0' )
                {
                    window.document.agileUploaderSWF.submit();
                }
                else
                {
                    document.getElementById( 'agileUploaderSWF' ).submit();
                }
            }

            return false;
        });
    });
//--><!]]>
</script>

</head>
<body>

<form id="agileUploaderSWF" name="agileUploaderSWF" method="post" action="http://your.action/script.php">
    <input type="text" id="agileUploaderSWF_text" name="agileUploaderSWF_text" />
</form>​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​

<a href="#" id="submitbutton"><img src="../images/user/create-product.png" border="0" /></a>​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​

</body>
</html>

    Hopefully this helps.

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