Question

So I’m declaring and initializing an int array:

static final int UN = 0;
int[] arr = new int[size];
for (int i = 0; i < size; i++) {
    arr[i] = UN;
}

Say I do this instead…

int[] arr = new int[5];
System.out.println(arr[0]);

… 0 will print to standard out. Also, if I do this:

static final int UN = 0;
int[] arr = new int[5];
System.out.println(arr[0]==UN);

… true will print to standard out. So how is Java initializing my array by default? Is it safe to assume that the default initialization is setting the array indices to 0 which would mean I don’t have to loop through the array and initialize it?

Thanks.

Answer 1

Everything in a Java program not explicitly set to something by the programmer, is initialized to a zero value.

• For references (anything that holds an object) that is null.
• For int/short/byte/long that is a 0.
• For float/double that is a 0.0
• For booleans that is a false.
• For char that is the null character '\u0000' (whose decimal equivalent is 0).

When you create an array of something, all entries are also zeroed. So your array contains five zeros right after it is created by new.

Note (based on comments): The Java Virtual Machine is not required to zero out the underlying memory when allocating local variables (this allows efficient stack operations if needed) so to avoid random values the Java Language Specification requires local variables to be initialized.