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Home/ Questions/Q 4624452
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T03:07:53+00:00 2026-05-22T03:07:53+00:00

So, the TreeMap class in java is of the form TreeMap<K,V> . Obviously K

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So, the TreeMap class in java is of the form TreeMap<K,V>. Obviously K needs to be a Combarable, but that is only checked at runtime with a cast, and if it not a Comparable an exception is thrown. Would it not have made more sense to define this class as TreeMap<K extends Comparable<? super K>, V>?

What am I missing here?

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  1. Editorial Team
    Editorial Team
    2026-05-22T03:07:54+00:00Added an answer on May 22, 2026 at 3:07 am

    An instance of TreeMap can be given a comparator for the keys, so they do not have to have a natural total ordering.

    [EDIT]

    More specifically, an instance of TreeMap can be created by providing the constructor with an instance of Comparator that is capable of comparing two keys for order. If you create a map in such a way, the comparator will be used for all key comparisons. In that case, the keys wouldn’t have to be inherently comparable.

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