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Home/ Questions/Q 8313159
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T20:23:53+00:00 2026-06-08T20:23:53+00:00

socket.on(‘data’, function(data, socket){ console.log(socket); worker.handle(data, socket); When I do this, the output is undefined

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        socket.on('data', function(data, socket){
        console.log(socket);
        worker.handle(data, socket);

When I do this, the output is undefined. Why do I get that instead of socket data?
This passes an (undefined) socket to my worker script, which then tries to write to that undefined socket, crashing the server.

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  1. Editorial Team
    Editorial Team
    2026-06-08T20:23:56+00:00Added an answer on June 8, 2026 at 8:23 pm

    Your callback is wrong. socket.on(‘data’) takes a function with just one parameter — the data. Your 2nd parameter is not valid and won’t be called.

    You should (IMHO) just be able to refer to your ‘socket’ variable within the context of the callback.

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