Question

Sorry about the stupid question however I can’t see/ not good enough to solve this:

I have a MYSQL db and a php form everything works but I can’t get out only one record – probably syntax error:

    $SQL = "SELECT * FROM massfelh WHERE user = $uname AND pass = md5($pword)"; - this is working
    $result = mysql_query($SQL); - this is too
    $catg = $result['categ']; - help
    $num_rows = mysql_num_rows($result); - this is ok too
    echo $catg; - for test and I can't print it on screen

DB structure: id, user, pass, categ

I only need the categ (either 1 or 0) but it just won’t show on screen.

Any help would be appreciated – and please say I am stupid too:)

Update:

thank you for everyone of you!!!!!!! Helped me a lot. I have fount the best solution for my code however all the reply was correct. Thanks again hop this will help to some one how is just as beginner as me:) thank you again

Answer 1

Try This..

$SQL = "SELECT * FROM massfelh WHERE user = $uname AND pass = md5($pword)"; 
    $result = mysql_query($SQL);
    $result = mysql_fetch_assoc($result);
    $catg = $result['categ'];
    $num_rows = mysql_num_rows($result); 
    echo $catg;