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Home/ Questions/Q 8183049
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T01:02:33+00:00 2026-06-07T01:02:33+00:00

Sorry I’m rather new to Spring Security. I’ve got the following applicationContext.xml <?xml version=1.0

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Sorry I’m rather new to Spring Security. I’ve got the following applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
            http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
            http://www.springframework.org/schema/context
            http://www.springframework.org/schema/context/spring-context-3.0.xsd
            http://www.springframework.org/schema/mvc 
            http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <!-- Activates various annotations to be detected in bean classes -->
    <context:annotation-config />

    <!-- Scans the classpath for annotated components that will be auto-registered as Spring beans.
     For example @Controller and @Service. Make sure to set the correct base-package-->
    <context:component-scan base-package="org.assessme.com" />

    <!-- Configures the annotation-driven Spring MVC Controller programming model.
    Note that, with Spring 3.0, this tag works in Servlet MVC only!  -->
    <mvc:annotation-driven /> 

</beans>

I’m following the tutorial on…

http://static.springsource.org/spring-security/site/tutorial.html

my question is, should I add to my existing applicationContext.xml or make a seperate XML file?

My web.xml is as follows…

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
  </context-param>
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>
  <servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>

I’m a little bit confused as in the tutorial, it specifies the context-param of the xml but I already have one declared, can I have more that one context-param? If someone could give me an idea of the best way to use springmvc and spring security together that would be great as at the moment I’m finding it hard to “merge” the xml files.

Thanks,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T01:02:37+00:00Added an answer on June 7, 2026 at 1:02 am

    You can have your security configuration in a separate file or combine with your existing application Context. If you want to use existing application context. You keep the default namespace as beans like this:

    <beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:security="http://www.springframework.org/schema/security"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
          http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
          http://www.springframework.org/schema/security
          http://www.springframework.org/schema/security/spring-security-3.1.xsd">
    
          <security:http auto-config="true">
             <security:intercept-url pattern="/**" access="ROLE_USER" />
          </security:http>
       ...
    </beans>
    

    and you have to prefix all security elements with security.

    But if you define in separate files. The advantage is you can have security as the default namespace and omit the security prefix like this:

     <beans:beans xmlns="http://www.springframework.org/schema/security"
        xmlns:beans="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://www.springframework.org/schema/beans
           http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
           http://www.springframework.org/schema/security
           http://www.springframework.org/schema/security/spring-security-3.1.xsd">
    
          <http auto-config='true'>
               <intercept-url pattern="/**" access="ROLE_USER" />
          </http>
          ...
    </beans:beans>
    

    The common way is to define file names like this:

     1)applicationContext.xml
     2)applicationContext-security.xml
    

    and in your web.xml like this:

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext*.xml</param-value>
    </context-param>
    

    or as a comma or space separated list also like below:

    <context-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/applicationContext.xml /WEB-INF/applicationContext-security.xml</param-value>
    </context-param>
    

    Documentation: ContextLoader

    Documentation: namespace config

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