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Home/ Questions/Q 232377
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:00:44+00:00 2026-05-11T20:00:44+00:00

Starting from an XML with a default namespace: <Root> <A>foo</A> <B></B> <C>bar</C> </Root> I

  • 0

Starting from an XML with a default namespace:

<Root>
  <A>foo</A>
  <B></B>
  <C>bar</C>
</Root>

I apply an XSLT to remove the ‘C’ element:

<?xml version="1.0" ?>

<xsl:stylesheet version="2.0" xmlns="http://www.w3.org/1999/XSL/Transform" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="html" indent="no" encoding="utf-8" />

<xsl:template match="*">
        <xsl:copy>
                <xsl:copy-of select="@*" />
                <xsl:apply-templates />
        </xsl:copy>
</xsl:template>

<xsl:template match="C" />

</xsl:stylesheet>

and I end up with the following XML (it’s OK to have ‘B’ not collapsed because I’m using HTML as output method):

<Root>
  <A>foo</A>
  <B></B>
</Root>

But then if I ever get another XML, this time with a namespace:

<Root xmlns="http://company.com">
  <A>foo</A>
  <B></B>
  <C>bar</C>
</Root>

the ‘C’ element is not removed after XSLT process.

What can I do to bypass this namespace, is there a way?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:00:44+00:00Added an answer on May 11, 2026 at 8:00 pm

    Not so recommendable, but works:

    <xsl:template match="*[local-name()='C']" />
    

    Better:

    <xsl:stylesheet 
      version="2.0" 
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
      xmlns:foo="http://company.com"
      exclude-result-prefixes="foo"
    >
    
      <!-- ... -->
    
      <xsl:template match="C | foo:C" />
    
      <!-- ... -->
    
    </xsl:stylesheet>
    
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