Question

String[] names=new String[4];
int[] scores=new int[4];
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter 4 strings and integers:");
for(int i=0;i<4;i++){
  names[i]=keyboard.nextLine();
  scores[i]= keyboard.nextInt();
}

Above is my simple program and the following shows the exception that pops up.

Enter 4 strings and integers:
first
1
second
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:909)
    at java.util.Scanner.next(Scanner.java:1530)
    at java.util.Scanner.nextInt(Scanner.java:2160)
    at java.util.Scanner.nextInt(Scanner.java:2119)
    at Q2.main(Q2.java:15)
Java Result: 1

Answer 1

nextInt doesn’t swallow the end of line, that stays in the buffer. So when you hit 1enter, 1 is read into the first score, then the second name is set to an empty string.

Then the parser tries to interpret second as an int, raising the exception.

You’ll need to discard the current line after the readInt.