Question

StringWriter  writer = new StringWriter();
XmlSerializer serializer = new KXmlSerializer();
serializer.setOutput(writer);
serializer.startDocument(null, null);
serializer.setFeature("http://xmlpull.org/v1/doc/features.html#indent-output", true);
// Creating XML

serializer.endDocument();
String xmlString = writer.toString();

In the above environment, whether there are any standard API’s available to remove the XML header <?xml version='1.0' ?> or do you suggest to go via string manipulation:

if (s.startsWith("<?xml ")) {
    s = s.substring(s.indexOf("?>") + 2);
}

Wanted the output in the xmlString without XML header info <?xml version='1.0' ?>.

Answer 1

If you use a JAXP serializer you get access to all the output properties defined in XSLT, for example omit-xml-declaration="yes". You can get this in the form of an “identity transformer”, called using transformerFactory.getTransformer() with no parameters, on which you then call setOutputProperty(). Another example:

TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty("omit-xml-declaration", "yes");