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Home/ Questions/Q 8297583
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T15:28:02+00:00 2026-06-08T15:28:02+00:00

struct that { that &frob() { return *this; } that frob() const { return

  • 0
struct that
{
    that &frob()
    {
        return *this;
    }
    that frob() const
    {
        return that(*this);
    }

    //that &&frob() && //<-called only if *this is an rvalue
    //{
    //    return move(*this);
    //}

    that()
    {
        // make things
    }
    that(const that &other)
    {
        // copy things
    }
    that(that &&other)
    {
        // move things
    }
};

Obviously the function in comments above is not legal C++, but I need to know if there is a way to accomplish this:

that().frob().frob().frob();

and so on, while each call to frob() would effectively call the “move” version thereof. As this is something that can be determined at compile time, I can’t think of any reason for it to not exist in some form.

I can write something like this:

that &&frob(that &&t)
{
    return t;
}

Which would result in this:

frob(frob(frob(that())));

Which is somewhat annoying to read and doesn’t accomplish my goal of “spelling things out” with delegation.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T15:28:03+00:00Added an answer on June 8, 2026 at 3:28 pm

    If you want the && annotated function to play well with others, you should use the & annotation on the others.

    that &frob() &
    {
        return *this;
    }
    that frob() const &
    {
        return that(*this);
    }
    
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