Question

Successfully created a string vector for storing the entries. A while loop asks for ToDo Items and a SHOW key shows the user all items currently stored in the string vector. For easier access to the items I have an int just displays “running” numbers in fron the items.

After user has added few items he can type DEL what brings him to the deletion mode:
(Here I like to enter 2 what will delete Stop Smoking and rearrange the array to fill
the gap)

Now I like to get the number the user enteres, decrement with 1 to match to the
vector array index number and delete the entry but whats the best approach to do this?

This is how I get the items added to the string vector:

int taskNumber = 1;
cout<<"New task: ";
getline (cin,newTaskEntry);
taskVector.push_back(newTaskEntry);

cout<<"TOTAL TASKS IN YOUR INBOX: "<<taskVector.size()<<endl;

This is how I show the user all entries:

for (vector<string>::iterator i = taskVector.begin(); i != taskVector.end(); ++i) 
            {
                cout<<taskNumber<<"  ";
                cout<<*i<<endl;
                taskNumber = taskNumber +1; 
            }

Answer 1

Do just:

cin >> number;
if(number > 0 && number < taskVector.size())
{
    vector<string>::iterator it(taskVector.begin() + number - 1);
    taskVector.erase(it);
}
else
    cout << "Error. Out of bounds\n";