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Home/ Questions/Q 733621
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:16:36+00:00 2026-05-14T07:16:36+00:00

Suppose code like this: class Base: def start(self): pass def stop(self) pass class A(Base):

  • 0

Suppose code like this:

class Base:
    def start(self):
        pass
    def stop(self)
        pass

class A(Base):
    def start(self):
        ... do something for A
    def stop(self)
        .... do something for A

class B(Base):
    def start(self):

    def stop(self):

a1 = A(); a2 = A()
b1 = B(); b2 = B()

all = [a1, b1, b2, a2,.....]

Now I want to call methods start and stop (maybe also others) for each object in the list all. Is there any elegant way for doing this except of writing a bunch of functions like

def start_all(all):
    for item in all:
        item.start()

def stop_all(all):
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:16:36+00:00Added an answer on May 14, 2026 at 7:16 am

    The *_all() functions are so simple that for a few methods I’d just write the functions. If you have lots of identical functions, you can write a generic function:

    def apply_on_all(seq, method, *args, **kwargs):
        for obj in seq:
             getattr(obj, method)(*args, **kwargs)
    

    Or create a function factory:

    def create_all_applier(method, doc=None):
        def on_all(seq, *args, **kwargs):
            for obj in seq:
                getattr(obj, method)(*args, **kwargs)
        on_all.__doc__ = doc
        return on_all
    
    start_all = create_all_applier('start', "Start all instances")
    stop_all = create_all_applier('stop', "Stop all instances")
    ...
    
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