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Home/ Questions/Q 4335200
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T10:38:13+00:00 2026-05-21T10:38:13+00:00

Supposed I have something like this readFile(…..&ol) //with overlapped while(1){ ////////….. waitforsingleobject(//ol.hevent); //// readfile(…..&ol)

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Supposed I have something like this

readFile(.....&ol) //with overlapped

while(1){

////////.....
waitforsingleobject(//ol.hevent);

////

readfile(.....&ol)

}

I noticed that both readfiles read from the beginning of the file…why? In a normal readfile without overlapped/asynchronization the second readfile would start off where the first ended..

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  1. Editorial Team
    Editorial Team
    2026-05-21T10:38:14+00:00Added an answer on May 21, 2026 at 10:38 am

    When using overlapped I/O on a file, you pass a pointer to an OVERLAPPED object, in this case ol.

    The OVERLAPPED struct has two variables, Offset and OffsetHigh. These two variables are combined into a 64-bit integer, with Offset being the lower-order DWORD and OffsetHigh being the high-order DWORD, and used as the offset to perform the I/O operation at.

    So, for example, if you wanted to start a ReadFile at the 8th byte of the file, you would set the Offset variable to 8 and the OffsetHigh variable to 0 before passing the OVERLAPPED to ReadFile.

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