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Home/ Questions/Q 531983
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:21:28+00:00 2026-05-13T09:21:28+00:00

/** * Testing Arrays * @author N002213F * @version 1.0 */ public class JavaArrays

  • 0
/**
 * Testing Arrays
 * @author N002213F
 * @version 1.0
 */
public class JavaArrays {

    public void processNames(String[] arg) {
        //-- patented method, stop, do not read ;)
    }

    public void test() {

        // works fine
        String[] names1 = new String[] { "Jane", "John" };
        processNames(names1);

        // works fine, nothing here
        String[] names2 = { "Jane", "John" };
        processNames(names2);

        // works again, please procced
        processNames(new String[] { "Jane", "John" });

        // fails, why, are there any reasons?
        processNames({ "Jane", "John" });

        // fails, but i thought Java 5 [vargs][1] handles this
        processNames("Jane", "John");
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-13T09:21:28+00:00Added an answer on May 13, 2026 at 9:21 am
    processNames({ "Jane", "John" });
    

    This fails, why, are there any reasons?

    You didn’t specify a type. Java doesn’t do type inference here; it expects you to specify that this is a string array. The answers to this question may help for this, too

    processNames("Jane", "John"); 
    

    This fails too, but I thought Java 5 varargs handles this

    If you want varargs, then you should write your method as such:

    public void processNames(String... arg)
    

    Note the ... instead of []. Just accepting an array doesn’t entitle you to use varargs on that method.

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