The default memory page size of the Linux kernel on x86 architecture was 4 KB, I wonder how was that calculated, and why ?
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The default page size is fixed by what the MMU (memory management unit) of the CPU supports. In 32-bit protected mode x86 supports two kinds of pages:
Not all x86 processors support large pages. One needs to have a CPU with Page Size Extension (PSE) capabilities. This excludes pre-Pentium processors. Virtually all current-generation x86 CPUs implements it.
4 KiB is widely popuplar page granularity in other architectures too. One could argue that this size comes from the division of a 32-bit virutal address into two 10-bit indexes in page directories/tables and the remaining 12 bits give the 4 KiB page size.