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Home/ Questions/Q 8246013
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T22:22:12+00:00 2026-06-07T22:22:12+00:00

The following basic code is working as expected. <?php mysql_connect(localhost, user, user@123) or die(mysql_error());

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The following basic code is working as expected.

<?php
mysql_connect("localhost", "user", "user@123") or die(mysql_error());
echo "Connected to MySQL<br />";
?>

What all I need is that instead of mysql_error, page not found 404 error should be returned.
I am looking for the shortest possible code since this is going to be used as load balancer check.

The following does not seem to work. I get a blank page.

mysql_connect("localhost", "user", "user@123") or die(header("HTTP/1.0 404 Not Found"));
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  1. Editorial Team
    Editorial Team
    2026-06-07T22:22:13+00:00Added an answer on June 7, 2026 at 10:22 pm

    I would do the following: bearing in mind I am using mysqli instead, the use of mysql_* is highly discouraged.

    $mysqli = new mysqli('localhost', 'user', 'password', 'dbname');
    
    if ($mysqli->connect_error) {
        header("HTTP/1.0 404 Not Found");
    } else {
    
    }
    

    Are you sure you want to return a 404 though, this is misleading as the resource has been found, I would be returning a 500 error as a server error which would be more appropriate.

    For a list of HTTP status codes see here

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