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Home/ Questions/Q 5988129
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:54:56+00:00 2026-05-22T22:54:56+00:00

The following code should be pretty self-evident. What I have made up so far

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The following code should be pretty self-evident. What I have made up so far to compute Y with variable x and some constants:

public static void main(String[] args) {
    int x=50;
    String str="100-x+200";
    str=str.replaceAll("x", Integer.toString(x));
    String [] arrComputeNumber = str.split("[-|+]");
    String [] arrComputeOperator = str.split("[\\d]");
    int y=Integer.parseInt(arrComputeNumber[0]);
    for (int i = 0; i < arrComputeOperator.length; i++) {
        if (arrComputeOperator[i].equals("-")) {
            y-=Integer.parseInt(arrComputeNumber[i+1]);
        } else if (arrComputeOperator[i].equals("+")) {
            y+=Integer.parseInt(arrComputeNumber[i+1]); 
        }
    }
    System.out.println("y="+y);
}

Unfortunately it doesn’t work since str.split("[\\d]") extracts wrongly.

It it extracts correctly I assume that above code would function correctly. Anyway this implementation is merely trivial and doesn’t take parenthesis or +- combination (which becomes minus), etc. into consideration. I haven’t found any better ways. Do you know any better ways to evaluate string as mathematical expression in Java?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:54:57+00:00Added an answer on May 22, 2026 at 10:54 pm

    You can use BeanShell. It is a Java interpreter.

    Here is some code:

    Interpreter interpreter = new Interpreter();
    interpreter.eval("x = 50");
    interpreter.eval("result = 100 - x + 200");
    System.out.println(interpreter.get("result"));
    
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