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Home/ Questions/Q 8262651
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T03:49:32+00:00 2026-06-08T03:49:32+00:00

The Haskell code below works fine. data Point = Point Float Float deriving (Show)

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The Haskell code below works fine.

data Point = Point Float Float deriving (Show)  
data Shape = Circle Point Float  
surface :: Shape -> Float  
surface (Circle _ r) = pi * r ^ 2  

Result:

*Main> surface $ Circle (Point 0 0) 10  
314.15927  

The Haskell code below does not work. Why? How to write surface function for Shape – Circle correctly?

data Point = Point Float Float deriving (Show)  
data Radius = Radius Float deriving (Show)

data Shape = Circle Point Radius   

surface :: Shape -> Float  
surface (Circle _ (Radius r)) = pi * (Radius r) ^ 2
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  1. Editorial Team
    Editorial Team
    2026-06-08T03:49:33+00:00Added an answer on June 8, 2026 at 3:49 am

    Your last line is constructing a Radius object and raising that to a power. Since you haven’t defined the power operator for Radius, that can’t work. Remove the constructor call:

    surface (Circle _ (Radius r)) = pi * r ^ 2
    
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