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Home/ Questions/Q 4343410
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T11:44:58+00:00 2026-05-21T11:44:58+00:00

The jQuery wrap() method does not wrap using element you created, but a duplicate:

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The jQuery wrap() method does not wrap using element you created, but a duplicate:

var $orig = $('p'); // some existing element
var $wrap = $('<div>').css({border:'1px solid red'});
$orig.wrap($wrap);
$wrap.append('<p>SMOKE YOU</p>'); // does not appear after the original element

If you are not convinced, you can see a live version of the above here: http://jsfiddle.net/QRmY6/

How do I best create non-trivial dynamic content to wrap around an existing node while retaining a reference to the wrapper that ends up around the content?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T11:44:59+00:00Added an answer on May 21, 2026 at 11:44 am

    The best alternatives I have come up with are:

    // Technique 1 - swap it out and then embed it via append
    var $wrap = $('<div>').css({border:'1px solid red'});
    $orig.replaceWith($wrap);
    $wrap.append($orig);
    
    // Technique 2 - create it inline and then modify it
    var $wrap = $orig.wrap('<div>').parent().css({border:'1px solid red'});
    
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