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Home/ Questions/Q 5966195
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T19:45:42+00:00 2026-05-22T19:45:42+00:00

The output is: Class A Class B printout Given code: class A(object): def __init__(self):

  • 0

The output is:

Class A
Class B
printout

Given code:

class A(object):
    def __init__(self):
        print "Class A"
    def printout(self):
        print "printout"

class B(A):
    def __init__(self):
        print "Class B"

def main():
    myA = A()
    myB = B()
    myB.printout()

if __name__ == '__main__':
    main()

I was hoping for:

Class A
Class A
Class B
printout

as result… :/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T19:45:43+00:00Added an answer on May 22, 2026 at 7:45 pm

    It’s because you did not call the superclass’s __init__.

    class B(A):
        def __init__(self):
            A.__init__(self)
    #       ^^^^^^^^^^^^^^^^ this have to be explicitly added
            print "Class B"
    

    In Python 3.x you could use super().__init__() instead of A.__init__(self), but you’re still explicitly invoking the superclass’s __init__.

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