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Home/ Questions/Q 8366695
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T12:58:44+00:00 2026-06-09T12:58:44+00:00

The problem: A loading message will appear when ajax request start: $(‘#container’).ajaxStart(function(){ showFlashMessage(); })

  • 0

The problem:

A loading message will appear when ajax request start:

$('#container').ajaxStart(function(){ showFlashMessage(); })

And will disappear after ajax request stops:

$('#container').ajaxStart(function(){ $('#flashMessage').remove(); })

Now I want to escape(ignore) the ajaxStart event after 3 ajax requests sent.

What I tried:

I tried following codes, but neither works:(

$('#container').ajaxStart(function(){})

or

$('#container').ajaxStop(function(){ $('#flashMessage').remove(); })

Question

How can I escape (ignore) the ajaxStart event?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T12:58:46+00:00Added an answer on June 9, 2026 at 12:58 pm

    Use a global counter variable.

    var count = 0;
    $('#container').ajaxStart(function(){
        if(count > 2) return false;
        showFlashMessage();
        count++;
    });
    
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