Question

The query which works looks like this :

SELECT     d.dosno, 
CAST(SUM(k.uur) + SUM(k.minuut) / 60 AS VARCHAR(4)) + 'u ' + 
CAST(SUM(k.minuut) % 60 AS VARCHAR     (2)) + 'm' AS derivedColumn
FROM         dbo.kbpres AS k INNER JOIN
dbo.doss AS d ON k.ino = d.ino
WHERE     (d.dosno = '93690')
GROUP BY d.dosno

I would like to add this :

(SUM(k.uur) * 60 + SUM(k.minuut)) * k.prijs AS TotalCost

but then I should add k.prijs to the groupby according to the error I get, but I don’t want this because then I get 21 results instead of just one totalresult.

example :

dosno    uur    minuut  prijs

93690    0      5       2

93690    1      0       1

93690    0      10      2

93690    0      5       5

result I need is :

93690    1:20     800

Answer 1

The answer is to add:

SUM((k.uur * 60 + k.minuut) * k.prijs) AS TotalCost

– to your query – this will derive the cost for each row and then sum those costs.

EDIT: to sum prijs only where soort is K, add:

SUM(case k.soort when 'K' then k.prijs end) AS FACKOSTEN

– to the existing query.